The purpose of this lab is to find the specific heat of the metal without having a flame or some form of heat directly on the metal. We find the specific heat with an equation q=mc(/\T), that is mass of water x the specific heat of water x the temperature change.Water holds heat longer then metals so the heat isn't directly on the metal
We were given the specific heats of water and metals.
Water - 4.184
Al- 0.897
Cu-0.385
Lead- 0.129
Brass- 0.385
Zn- 0.390
We did this by boiling a beaker of water with the metal inside on a hot plate till it got to a boil.
We then transferred the metal from the boiling water to another beaker of normal tap water with the initial temperature of 21.1°C.
With the metal in the in the new water the temperature change was low. Only by 1.4°C, so the beaker of water was then 22.5°C
A problem in our lab was transferring the metal from the boiling water to the second beaker, there was a loss of heat but that is common. Other then that there was not an error.
Our heat the water gained was:
120.737 H2O x 4.184 x 1.4 = 707.22905 J
In conclusion I got that our metal was lead.
Friday, May 24, 2013
Chemical Formula's
The Formulas that are hard for me to remember are the acids. A good way to remember an acd is that it has an H (hydrogen) at the front of it. The Acid also has to be balanced.
Example: Sulfate SO4
Add Hydrogen -> HSO4
Sulfates charge is -1 Hydrogen's charge is+1
So there is only one atom of sulfate and one of Hydrogen
Example: Phosphoric Acid
Phosphate: PO4
Phosphoric Acid: H3PO4
Since the charge on phosphate is -3, and the hydrogen +1 you have to have 3 hydrogen.
Example: Sulfate SO4
Add Hydrogen -> HSO4
Sulfates charge is -1 Hydrogen's charge is+1
So there is only one atom of sulfate and one of Hydrogen
Example: Phosphoric Acid
Phosphate: PO4
Phosphoric Acid: H3PO4
Since the charge on phosphate is -3, and the hydrogen +1 you have to have 3 hydrogen.
Tuesday, May 14, 2013
Lab Reaction Post
In this chemical reaction there are two clear aqueous chemicals Barium Chloride and Sodium Sulfate in a double replacement reaction. BaCl2 + NaSo4 = NaCl + BaSo4
I predicted it would make it a white/ grey color. I did not expect it to turn grey only where a single drop was, I thought it would just turn all of it grey with a single drop but I didn't try and stir it around. I did end up turning a grey foggy color.
The picture isn't completely clear but with a single drop of the barium chloride it turns a grey in the spot in it dropped and slowly expands around in the rest of the Sodium Sulfate.
I predicted it would make it a white/ grey color. I did not expect it to turn grey only where a single drop was, I thought it would just turn all of it grey with a single drop but I didn't try and stir it around. I did end up turning a grey foggy color.
The picture isn't completely clear but with a single drop of the barium chloride it turns a grey in the spot in it dropped and slowly expands around in the rest of the Sodium Sulfate.
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